🏡 index : github.com/captn3m0/codechef.git

---
category_name: school
problem_code: SINS
problem_name: 'The Deadly Sin'
languages_supported:
    - C
    - CPP14
    - JAVA
    - PYTH
    - 'PYTH 3.5'
    - PYPY
    - CS2
    - 'PAS fpc'
    - 'PAS gpc'
    - RUBY
    - PHP
    - GO
    - NODEJS
    - HASK
    - rust
    - SCALA
    - swift
    - D
    - PERL
    - FORT
    - WSPC
    - ADA
    - CAML
    - ICK
    - BF
    - ASM
    - CLPS
    - PRLG
    - ICON
    - 'SCM qobi'
    - PIKE
    - ST
    - NICE
    - LUA
    - BASH
    - NEM
    - 'LISP sbcl'
    - 'LISP clisp'
    - 'SCM guile'
    - JS
    - ERL
    - TCL
    - kotlin
    - PERL6
    - TEXT
    - 'SCM chicken'
    - CLOJ
    - COB
    - FS
max_timelimit: '1'
source_sizelimit: '50000'
problem_author: kr_abhinav
problem_tester: null
date_added: 3-04-2018
tags:
    - kr_abhinav
time:
    view_start_date: 1522873800
    submit_start_date: 1522873800
    visible_start_date: 1522873800
    end_date: 1735669800
    current: 1525198879
is_direct_submittable: false
layout: problem
---
All submissions for this problem are available.Meliodas and Ban are fighting over chocolates. Meliodas has $X$ chocolates, while Ban has $Y$. Whoever has lesser number of chocolates eats as many chocolates as he has from the other's collection. This eatfest war continues till either they have the \_\_same number of chocolates\_\_, or atleast one of them is left with \_\_no chocolates\_\_. Can you help Elizabeth predict the total no of chocolates they'll be left with at the end of their war? ###Input: - First line will contain $T$, number of testcases. Then the testcases follow. - Each testcase contains of a single line of input, which contains two integers $X, Y$, the no of chocolates Meliodas and Ban have, respectively. ###Output: For each testcase, output in a single line the no of chocolates that remain after Ban and Meliodas stop fighting. ###Constraints - $1 \\leq T \\leq 100000$ - $0 \\leq X,Y \\leq 10^9$ ###Sample Input: 3 5 3 10 10 4 8 ###Sample Output: 2 20 8 ###EXPLANATION: Denoting Meliodas as $M$, Ban as $B$. Testcase 1: $M$=5, $B$=3 Ban eates 3 chocolates of Meliodas. $M$=2, $B$=3 Meliodas eats 2 chocolates of Ban. $M$=2, $B$=1 Ban eates 1 chocolate of Meliodas. $M$=1, $B$=1 Since they have the same no of candies, they stop quarreling. Total candies left: 2 Testcase 2: $M$=10, $B$=10 Since both of them had the same candies to begin with, there was no point in fighting. Total candies left: 20 Testcase 3: $M$=4, $B$=8 Meliodas eats 4 chocolates of Ban. $M$=4, $B$=4 Since they have the same no of candies, they stop quarreling. Total candies left: 8