---
category_name: hard
problem_code: SUBQUERY
problem_name: 'Substring Query'
languages_supported:
- ADA
- ASM
- BASH
- BF
- C
- 'C99 strict'
- CAML
- CLOJ
- CLPS
- 'CPP 4.3.2'
- 'CPP 4.9.2'
- CPP14
- CS2
- D
- ERL
- FORT
- FS
- GO
- HASK
- ICK
- ICON
- JAVA
- JS
- 'LISP clisp'
- 'LISP sbcl'
- LUA
- NEM
- NICE
- NODEJS
- 'PAS fpc'
- 'PAS gpc'
- PERL
- PERL6
- PHP
- PIKE
- PRLG
- PYTH
- 'PYTH 3.4'
- RUBY
- SCALA
- 'SCM guile'
- 'SCM qobi'
- ST
- TCL
- TEXT
- WSPC
max_timelimit: '1'
source_sizelimit: '50000'
problem_author: xcwgf666
problem_tester: furko
date_added: 5-06-2014
tags:
- ltime13
- medium
- suffix_automata
- trie
- xcwgf666
editorial_url: 'http://discuss.codechef.com/problems/SUBQUERY'
time:
view_start_date: 1404030600
submit_start_date: 1404030600
visible_start_date: 1404030600
end_date: 1735669800
current: 1493556860
layout: problem
---
All submissions for this problem are available.### Read problems statements in [Mandarin Chinese](http://www.codechef.com/download/translated/LTIME13/mandarin/SUBQUERY.pdf) and [Russian](http://www.codechef.com/download/translated/LTIME13/russian/SUBQUERY.pdf).
You are given a string **S** and **N** queries. Each query is defined by two integers - **Li** and **Pi**. Count the number of strings of the length **Li** that occur **exactly Pi** times (as the consecutive substrings) in the string **S**.
### Input
The first line of input contains the string **S**.
The second line of input contains the integer **N** - the number of queries.
Then there are **N** lines, the **i**-th one contains numbers **Li** and **Pi** for the **i**-th query.
### Output
For each query output the answer at the corresponding line of the output.
### Constraints
- **1** ≤ **|S|** ≤ **50**, **1** ≤ **N** ≤ **100** : 13 points.
- **1** ≤ **|S|** ≤ **1000**, **1** ≤ **N** ≤ **10000** : 27 points.
- **1** ≤ **|S|** ≤ **200000**, **1** ≤ **N** ≤ **500000** : 60 points.
- **1** ≤ **Li**, **Pi** ≤ **N**
### Example
<pre><b>Input:</b>
abacaba
1
3 2
<b>Output:</b>
1
</pre>### Explanation
The only such string is **aba**.