---
{"category_name":"easy","problem_code":"ALLDIV3","problem_name":"Make it Divisible","problemComponents":{"constraints":"- $1 \\leq T \\leq 1000$\n- $2 \\leq N \\leq 10^5$\n- $1 \\leq A_i \\leq 10^9$\n- Sum of $N$ over all test cases does not exceed $2 \\cdot 10^5$","constraintsState":true,"subtasks":"- 30 points : $1 \\leq R \\leq 10000$\n- 70 points : $1 \\leq R \\leq 10^9$\n","subtasksState":false,"inputFormat":"- The first line will contain $T$, the number of test cases. Then the test cases follow.\n- The first line of each test case contains $N$, denoting the length of the array.\n- The second line of each testcase contains $N$ space separated integers $A_i$.\n","inputFormatState":true,"outputFormat":"Output the minimum number of operations required to make all numbers divisible by $3$.\n\nIf it is not possible to make every number divisible by $3$, then output $-1$.","outputFormatState":true,"sampleTestCases":{"0":{"id":1,"input":"3\n3\n1 2 3\n4\n6 3 9 12\n2\n4 3\n","output":"1\n0\n-1\n","explanation":"**Test Case $1$:** Chef can select the indices $2$ and $1$ and thus increase $A_2$ by $1$ and decrease $A_1$ by $1$. Thus the array becomes $[0,3,3]$. So every number is now divisible by $3$.\n\n**Test Case $2$:** Since all the numbers are already multiples of $3$, Chef will not need to apply the operation at all.\n\n**Test Case $3$:** There is no way to make all the numbers a multiple of $3$.","isDeleted":false}}},"video_editorial_url":"https://youtu.be/LtMdieYBW24","languages_supported":{"0":"CPP14","1":"C","2":"JAVA","3":"PYTH 3.6","4":"CPP17","5":"PYTH","6":"PYP3","7":"CS2","8":"ADA","9":"PYPY","10":"TEXT","11":"PAS fpc","12":"NODEJS","13":"RUBY","14":"PHP","15":"GO","16":"HASK","17":"TCL","18":"PERL","19":"SCALA","20":"LUA","21":"kotlin","22":"BASH","23":"JS","24":"LISP sbcl","25":"rust","26":"PAS gpc","27":"BF","28":"CLOJ","29":"R","30":"D","31":"CAML","32":"FORT","33":"ASM","34":"swift","35":"FS","36":"WSPC","37":"LISP clisp","38":"SQL","39":"SCM guile","40":"PERL6","41":"ERL","42":"CLPS","43":"ICK","44":"NICE","45":"PRLG","46":"ICON","47":"COB","48":"SCM chicken","49":"PIKE","50":"SCM qobi","51":"ST","52":"SQLQ","53":"NEM"},"max_timelimit":1,"source_sizelimit":50000,"problem_author":"utkarsh_adm","problem_tester":"","date_added":"20-11-2021","tags":{"0":"cook135","1":"simple","2":"utkarsh_adm"},"problem_difficulty_level":"Unavailable","best_tag":"","editorial_url":"https://discuss.codechef.com/problems/ALLDIV3","time":{"view_start_date":1637519400,"submit_start_date":1637519400,"visible_start_date":1637519400,"end_date":1735669800},"is_direct_submittable":false,"problemDiscussURL":"https://discuss.codechef.com/search?q=ALLDIV3","is_proctored":false,"visitedContests":{},"layout":"problem"}
---
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Tracy is teaching Charlie maths via a game called $N$-Cube, which involves three sections involving $N$.
Tracy gives Charlie a number $N$, and Charlie makes a list of $N$-th powers of integers in increasing order $1^N, 2^N, 3^N, \dot, \text{so on}$. This teaches him exponentiation.
Then Charlie performs the following subtraction game $N$ times: Take all pairs of consecutive numbers in the list and take their difference. These differences then form the new list for the next iteration of the game. Eg, if $N$ was 6, the list proceeds as $[1, 64, 729, 4096 ... ]$ to $[63, 685, 3367 ...]$, and so on $5$ more times.
After the subtraction game, Charlie has to correctly tell Tracy the $N$-th element of the list. This number is the *value of the game*.
After practice Charlie became an expert in the game. To challenge him more, Tracy will give two numbers $M$ (where $M$ is a prime) and $R$ instead of just a single number $N$, and the game must start from $M_R - 1$ instead of $N$. Since the *value of the game* can now become large, Charlie just have to tell the largest integer $K$ such that $M_K$ divides this number. Since even $K$ can be large, output $K$ modulo 1000000007 ($10^9 + 7$).
<aside style='background: #f8f8f8;padding: 10px 15px;'><div>All submissions for this problem are available.</div></aside>